Lecture , Tuesday 1999/11/30, 8:00-9:50 AM:

Showed by \epsilon - \delta that f(x) = sqrt( abs(x) ) is uniformly
continuous. 
Also quote the theorem on compact sets for a short proof
Gave well known examples of discont functions.
(1)  f(x) = 0 on irrationals, 1 otherwise.
(2)  f(x) = 0 on rationals, 1/p on x = q/p.

seperate continuous and jointly continuous.

1-d calculus, 
eg: cont, but not diffrentiable at 0
    differentiable but not continuously diff at 0.