function Q3(n)
	
	b = 1.5;
	g = @(x) b * x + (1-b) * (3 * sin(x) + 0.01);
	P0 = 1;
	for i  = 1:n
			P = g(P0);
			printf("n = %2.0f, P = %16.15f\n", i, P);
			P0 = P;
	end
	
end

%Result:
%b = 1.5  P0 = 1   n =  5,  P = -0.005000031250547
%b = 1.8  P0 = 1   n = 67, P = -0.005000031250547
%Actually there are three solutions near -2, 0 ,2 (see the figure).